cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
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cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~co
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
cos1°+cos2°+cos3°+……cos180°=_______
谢谢大家,给出过程吧~~~~
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
cos1°=-cos179,
cos2°=-cos178
.
cos89°=-cos91°
原式正负相抵后,仅余下:
cos90°+cos180°=0-1=-1
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
Cos1°+cos2°+cos3°+……cos89°=
cos1°+cos2°+cos3°.+co180°=?
cos1°+cos2°+cos3°+.+cos360°
cos1°+cos2°+cos3°+...+cos179°化简
cos1°+cos2°+cos3°+.+cos359°等于多少.
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
cos1°×cos1°+cos2°×cos2°+……+cosn
求cos1+cos2+cos3+…+cos178+cos179的值
(sin1°-cos1°)(sin2°-cos2°)(sin3°-cos3°)……(sin89°-cos89°)=一定要告诉我原因啊 谢谢最后得0.
cos1°的二次方+cos2°的二次方+cos3°的二次方+……cos89°的二次方=
cos1°²+cos2°²+cos3°²+cos4°²...+cos89°²=?
cos1°+cos2°+cos3°+...+cos²89°过程和答案!速度啊 多谢!
cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
cos1°+cos2°+cos3°+...+cos180°的值为?
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
求cos1º+cos2º+cos3º+……+cos178º+cos179º的值
cos0度+cos1度+cos2度+cos3度+…cos358度+cos359度+cos360度