f'(cos^2x)=sin^2x ,f(0)=0,求f(x)
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f''(cos^2x)=sin^2x,f(0)=0,求f(x)f''(cos^2x)=sin^2x,f(0)=0,求f(x)f''(cos^2x)=sin^2x,f(0)=0,求f(x)f''(cos^2x)
f'(cos^2x)=sin^2x ,f(0)=0,求f(x)
f'(cos^2x)=sin^2x ,f(0)=0,求f(x)
f'(cos^2x)=sin^2x ,f(0)=0,求f(x)
f'(cos^2x)=sin^2x=1-cos^2x
所以f'(x)=1-x
所以f(x)=∫(1-x)dx=x-x^2/2+C
f(0)=0-0+C=0
所以f(x)=x-x^2/2
f'(cos^2x)=sin^2x=1-cos^2x
所以f'(x)=1-x
所以f(x)=∫(1-x)dx=x-x^2/2+C
f(0)=0-0+C=0
所以f(x)=x-x^2/2 1
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