题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]=2sin(π/4x+π/4)+2cos(π/4x+π/4)=2倍根号2*sin(π/4+π/2)

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题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]=2sin(π/4x+π/4)+2cos(π/4x+π/4)=2倍根号2*sin(π/4+π/2)题目是这样:sin(π/4

题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]=2sin(π/4x+π/4)+2cos(π/4x+π/4)=2倍根号2*sin(π/4+π/2)
题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]
=2sin(π/4x+π/4)+2cos(π/4x+π/4)
=2倍根号2*sin(π/4+π/2)

题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]=2sin(π/4x+π/4)+2cos(π/4x+π/4)=2倍根号2*sin(π/4+π/2)
题呢?

题目是这样:sin(π/4x+π/4)+2sin[π/4(x+2)+π/4]=2sin(π/4x+π/4)+2cos(π/4x+π/4)=2倍根号2*sin(π/4+π/2) 高中数学关于三角代换求值域的问题题目是这样的,函数f(x)=2√x + √(4-x)的值域为?这个定义域是[0,4],然后令x=4(sinα)^2,然后为什么α属于[0,π/2] 像这样的三角换元不是应该sinα是α属于[-π/2,π/2], 已知(45度+x)=4/5,且3π/4<x<π,求[cos(45度+x)]/[cos平方x-sin平方x]的值.答案为-5/6 恩 题目上这样写的~ 一道关于三角函数对称轴的题目.y=2sin(2x+π/2)是偶函数,因为当x=0的时候函数能取到最值.那按照这样推理,y=2sin(3x+π/2)也是偶函数了.但是我们知道y=2sin(3x+π/2)=2sin{3(x+π/6)} 也就是 化简f(x)=2cosx/sin(π/4-π/2) 要详细过程 谢谢啊sorry sorry!我打错题目了是 f(x)=2cosx/sin(π/4-x/2) sin(x+π/4) Y=X+√1-X² 值域为?解是这样的 设X=sin a .a∈[-π/2,π/2] .则Y=sin a+ cos a=√2 sin(a+π/4).a+π/4∈[-π/4,3π/4] 所以Sin a(a+π/4)的最大值是1 最小值是-√2 /2 数学题目已知函数f(x)=+2sinωxcosωx+2f(a)=2/3求sin(5/6π-4a) 求sin^2(2x+π/3)的导数这样写为什么不对:[sin^2(2x+π/3)]'=[sin(2x+π/3)·sin(2x+π/3)]'=2[sin(2x+π/3)]'·sin(2x+π/3)=2cos(2x+π/3)·sin(2x+π/3)=sin(4x+2π/3) 数学函数周期性和诱导公式f(x)=sin(2x-4/π)这个函数周期是π,所以sin(2x-4/π)=sin(2x-4/π+π)但是如果把sin(2x-4/π+π)按诱导公式下去算不是应该等于-sin(2x-4/π)吗?这样sin(2x-4/π)=sin(2x-4/π+π)根本不可能 f(x)=sin²(x+π/4)-sin²(x-π/4)是 sin(x-π/4 + π/2 )=-cos(x+π/4) 为什么会这样 sin的+π/2 不是会变 cos 为什么会这样啊?主要是不知道那个负号! 数学题f(x)=2sin^(π/4 x)-√3cos2x-1已知f(x)=2sin^(π/4 x)-√3cos2x-1 x属于R,1.求函数f(x)的最小正周期2.若对任意X属于{π/4,π/2},不等式f(x)>m^2-3m+3恒成立,求实数m的取值范围!题目是f(x)=2sin^2(π/4 +x)-√ 化简sin(x+7π/4)+cos(x-3π/4)步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2- 2sin(x-π/4)sin(x+π/4)=?答案是-cos2x 还是cos2x 关于函数y=sin(x+π/4)+sin(π/4-x),是奇函数还是偶函数 2sin(x+π/4)sin(x-π/4)=? sin(x+π/4)sin(x-π/4)等于什么?