巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/27 02:38:54
巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!巧解(3-5)^
巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!
巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101
一定要是巧解!
巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!
原式=[(-2)×1/2]^2+[(-0.125)×(-8)]^100×(-8)
=(-1)^2+1^100×(-8)
=1+(-8)
=-7
巧解(3-5)^2*(1/2)^2+(-0.125)^100*(-8)^101一定要是巧解!
1+5+5+5+5+3+2+2+2+2+2+2+1+2+5
1-3/5+1/2-2/5
1、2、3、5,
[-2*1/4+(-1/2)3]*(-2*2/3)+(-1*2/3)2÷5/3
(-2/3)+1/2+4/5+(-1/2)+(-1/3)
1 2 3 4 5 1 2
1+1+2+2+3+4+5
1+1+2+3*5
(-1/2)+(-2/5)+(+3/2)+(18/5)+(39/5)
2^1/2 、3^1/3 和5^1/5
计算1^2-2^2+3^2-4^2+5^2-6^2+...+(2n-1)^2-(2n)^2
3/(1^2)+5/(1^2+2^2)+7/(1^2+2^2+3^2)+.+(2n+1)/(1^2+2^2+.n^2)=?
1^2+3^2+5^2+.+N^2=多少
2+ 2^3 +2^5 +...+(2^2n-3) +(2^2n-1)=?
1*2^1+2*2^2+3*2^3+4*2^4+5*2^5+.+2012*2^2012=?
(1/2)^-2-(1/根号5+2)^0+(3X10^-2)^4/(3X10^-5)^2
化简:(2x+1)^2+5(x-1)^2-(3x+2)(3x-2)+2