x2-(1+2根号3)x+根号3(1-根号3)=0

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x2-(1+2根号3)x+根号3(1-根号3)=0x2-(1+2根号3)x+根号3(1-根号3)=0x2-(1+2根号3)x+根号3(1-根号3)=0x²-(1+2√3)x+√3(1-√3)

x2-(1+2根号3)x+根号3(1-根号3)=0
x2-(1+2根号3)x+根号3(1-根号3)=0

x2-(1+2根号3)x+根号3(1-根号3)=0
x²-(1+2√3)x+√3(1-√3)=0
x²+[-√3+(1-√3)]x +√3(1-√3)=0
(x-√3)[x-(1-√3)]=0
解得
x= √ 3 或 x =1-√3