若/x-1/+/y+2/+/z-3/=0,则(x+1)(y-2)(z-3)的值为多少

若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 若|x-3|+|y+2|+|2z+1|=0,求(xy-yz)(y-x+z) 三元一次方程组题目x+y-z=11 y+z-x=5 x-y+z=1x+y=4 y+z=3 x+z=5若已知x-3y+2z=0 2x+3y-8z=0, 且xyz≠0,则x:y:z= 若有理数x,y,z满足等式：（x-1)^2+(2x-y)^2+|3x-z|=0,求x+y+z的值 若有理数x、y、z满足等式(x-1)^2+(2x-y)^4+|x-3z|=0,求x、y、z的值 若有理数x,y,z满足等式：（x-1)的平方+（2x-y)的平方+｜3x-z｜=0,求x+y+z的值 若有理数x,y,z满足(x-1)的平方+|2x-y|+|x-3z|=0,求x+y+z的值 方程组 (1) x+2y-3z=12 x-3y+2z= - 13 x-y-z=0 (2) x+ y=z 5x-y+z=18 2x+5y+3z= -1 (1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1. 已知xyz≥0,x+y+z=1,化简x（2y-z）/(1+x+3y)+y(2z-x) /(1+y+3z) +z(2x-y)/(1+z+3x) 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 若实数XYZ满足2|x-y|+√2y+z+z方-z+1//4=0 求X+Y+Z 2y+z在根号里 若方程组2x+3y-z=0,x-3y-z=0,则x：y：z=? 若方程组：x+y-2z=0,3x+y-z=0,则x：y：z= 2x-2y+z=0 2x+y-z=1 x+3y-2z=1 x+2y+z=3y+2x-z=0z-2y-3x=-1 {2x-2y+z=0,2x+y-z+1,x+3y-2z=1 x+2y+z=0 x-y+2z=2 2x-y+3z=-1