x*(40-x)/2=180
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x*(40-x)/2=180x*(40-x)/2=180x*(40-x)/2=180∵x*(40-x)/2=180==>40x-x²=360==>x²-40x=360==>x&su
x*(40-x)/2=180
x*(40-x)/2=180
x*(40-x)/2=180
∵x*(40-x)/2=180
==>40x-x²=360
==>x²-40x=360
==>x²-40x+400=760
==>(x-20)²=760
==>x-20=±2√190
==>x=20±2√190
==>x=2(10±√190)
∴原方程的解是:x=2(10±√190)
40x-x^2=360
x^2-40x+360=0
判别式=1600-1440=160
x=20±2√10
x+40=2x x=?
x*(40-x)/2=180
2x+40%x=180
(x-2)+(x+2)+(x/2)+(2*x)=180
(180x-36*x)/(x+2x)*2x=(180x-36*x)/(x+2x)*x+36x 这个怎么解啊····
180=( )x( )x( )x( ) ×( )
f(x)=x^2+x (x
① (x-5)/8+40=(x-5)/6② x+(3x+1)+(x/2 -1)=180
x-40%x=
x^2=x
(35-X)*(40-2X)+40X+2X*(35-X)=35*40
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
解分式方程:1/X-2+1/X-6=1/X-7+1/X-11/X-2+1/X-6=1/X-7+1/X-11/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)(x-1-x+2)/(x-2)(x-1)=(x-6-x+7)/(x-7)(x-6)1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)x^2-3x+2=x^2-13x+4213x-3x=42-210x=40x=4 为什么要移向才能解
x{x+1}{x-1}}x-2}{x-3}-40
x/x平方-x+2=2x/x+1
f(x)=x|x|+2x (x
(X+1)X(X+2)X(X+3)=504