∫dx/sin^2(2x-3)=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 15:49:44
∫dx/sin^2(2x-3)=?∫dx/sin^2(2x-3)=?∫dx/sin^2(2x-3)=?由于dx=d(2x-3)/2所以Int(dx/sin(2x-3)^2)=Int(d(2x-3)/s
∫dx/sin^2(2x-3)=?
∫dx/sin^2(2x-3)=?
∫dx/sin^2(2x-3)=?
由于dx=d(2x-3)/2
所以
Int(dx/sin(2x-3)^2)
=Int(d(2x-3)/sin(2x-3)^2)/2
=-cot(2x-3)/2+C
(tanx)'=(secx)^2
(cotx)'=-(cscx)^2
d(2x-3)=2dx
∫dx/sin^2(2x-3)=1/2∫csc^2(2x-3) d(2x-3)=-1/2*cot(2x-3)+C
∫sin^3(x)cos^2(x)dx=
∫sin(6x)sin(2x)dx=?
∫(2/sin^2x)dx=
∫dx/sin^2(2x-3)=?
不定积分:∫dx/(3+sin^2x)=
∫x/sin^2(x) dx
∫sin(x) cos^2(x)dx
∫(cot^2 x/sin^2 x)dx=?
∫(cos^3x/sin^2x)dx
∫(x^3 )*(sin x^2) dx 求不定积分
∫ [cos^3(x)]/[sin^2 (x)]dx
求积分:∫sin^2 (x) /cos^3 (x) dx
高数∫(x^2)(sin[x^3])dx
∫sin^2x/(1+sin^2x )dx求解,
∫(1-sin^2( x/2))dx
求∫ sin^2 x/2 dx ..
∫sin^3(x)dx=?
求不定积分:∫sin(x^2)dx