若x^2-4xy+5y^2-2y+1=0,求a.b的值若x^2-4xy+5y^2-2y+1=0,求x.y的值
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若x^2-4xy+5y^2-2y+1=0,求a.b的值若x^2-4xy+5y^2-2y+1=0,求x.y的值若x^2-4xy+5y^2-2y+1=0,求a.b的值若x^2-4xy+5y^2-2y+1=
若x^2-4xy+5y^2-2y+1=0,求a.b的值若x^2-4xy+5y^2-2y+1=0,求x.y的值
若x^2-4xy+5y^2-2y+1=0,求a.b的值
若x^2-4xy+5y^2-2y+1=0,求x.y的值
若x^2-4xy+5y^2-2y+1=0,求a.b的值若x^2-4xy+5y^2-2y+1=0,求x.y的值
x^-4xy+5y^2-2y+1
=(x^2-4xy+4y^2)+(y^2-2y+1)
=(x-2y)^2+(y-1)^2=0
因为两非负之和为零,所以
x-2y=0
y-1=0
所以
x=2
y=1
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