(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
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(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-6)=1
两边各乘以0.3,则
1.5y-1-0,09y+1.8=0.3
y=-50/141
原式为 5y-1/0.3-0.3y+0.12/0.02=1
化简得 5y - 10/3 - 3/10y +6=1
同乘30 150y - 100-9y + 180=30
化简得 141y=-50
y= -(50/141)
-0.7y+0.2=-0.3y+0.1 y=?
-0.7y+0.2= -0.3y+0.1
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
已知x:y=0.5:0.3,y:z=1/5:1/2,求x:y:
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y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
解方程3y=1/3+3=3y+5/4-y-4/60-1/26-3y/0.3+2-6y/0.4=1-3y-4/0.5
4y^4-4x^3+0.2x^2y^2+xy^3-1/5x^2y^2-4y^4-x^3y,其中x=-2,y=0.3.
0.3x+0.2y=1 解方程组{ 5x+7y=400.3x+0.2y=1解方程组{5x+7y=40
matlab高手帮忙看程序!我要画matlab图,f 随x,y变化,怎么不会出现图形呢,程序如下,请大师帮忙看程序哪里出错了,clcx=0:0.2:10;y=x;f=x.^5.*y.^5.*0.1.^(y-1).*0.3.^(y-1).*0.5.^(y-1).*0.8.^(y-1).*0.9.^(y-1).*exp(-x.*(0.1.^y
0.4y+0.9-0.3分之0.3+0.2y=1
0.4y+0.9/0.5-0.3+0.2y/0.3=1
-y - y/1-y +1
0.4y+0.9/0.5 - 0.3-0.2y/0.3=1(0.4y+0.9)/0.5 - (0.3-0.2y)/0.3=1