(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 12:31:15
(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0.3)-(0.3y-0.12/0.02)=1求y(5y-1/0
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1
(5y-10/3)-(0.3y-6)=1
5y-10/3-0.3y+6=1
5y-0.3y=1+10/3-6
4.7y= -5/3
y= -5/3÷4.7
y= - 50/141
y= 负141分之50
-0.7y+0.2=-0.3y+0.1 y=?
-0.7y+0.2= -0.3y+0.1
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
(5y-1/0.3)-(0.3y-0.12/0.02)=1 求y
已知x:y=0.5:0.3,y:z=1/5:1/2,求x:y:
··0.4y+0.9/0.5-y-5/2=0.3+0.2y/0.3求y
·0.4y+0.9/0.5-y-5/2=0.3+0.2y/0.3求y
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
解方程3y=1/3+3=3y+5/4-y-4/60-1/26-3y/0.3+2-6y/0.4=1-3y-4/0.5
4y^4-4x^3+0.2x^2y^2+xy^3-1/5x^2y^2-4y^4-x^3y,其中x=-2,y=0.3.
0.3x+0.2y=1 解方程组{ 5x+7y=400.3x+0.2y=1解方程组{5x+7y=40
matlab高手帮忙看程序!我要画matlab图,f 随x,y变化,怎么不会出现图形呢,程序如下,请大师帮忙看程序哪里出错了,clcx=0:0.2:10;y=x;f=x.^5.*y.^5.*0.1.^(y-1).*0.3.^(y-1).*0.5.^(y-1).*0.8.^(y-1).*0.9.^(y-1).*exp(-x.*(0.1.^y
0.4y+0.9-0.3分之0.3+0.2y=1
0.4y+0.9/0.5-0.3+0.2y/0.3=1
-y - y/1-y +1
0.4y+0.9/0.5 - 0.3-0.2y/0.3=1(0.4y+0.9)/0.5 - (0.3-0.2y)/0.3=1