(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-B= (2)3X2-X=1,则6X3+7X2-5X+2008=
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(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-B=(2)3X2-X=1,则6X3+7X2-5X+2008=(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-
(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-B= (2)3X2-X=1,则6X3+7X2-5X+2008=
(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-B= (2)3X2-X=1,则6X3+7X2-5X+2008=
(1)2X+3)/(X-1)(X+2)=A/x-4+B/x+2,那A-B= (2)3X2-X=1,则6X3+7X2-5X+2008=
(1)
(2X+3)/(X-1)(X+2)=(2X-2+5)/(X-1)(X+2)=5/3(X-1)+1/3(x+2)
由A/x-1=5/3(X-1) B/x+2= 1/3(x+2)
A=5/3 B=1/3 A-B=4/3
(2)
6X3+7X2-5X+2008=6X3-2X2+9X2-5X+2008
=2X(3X2-X)+9X2-5X+2008
=2X+9X2-5X+2008
=3(3X2-X)+2008
=3+2008
=2011
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(X+1)X(X+2)X(X+3)=504
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一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
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x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
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x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,