设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=

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设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=设数列{an}的前n项和为S

设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=
设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=

设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=
应该是“Sn=2an+Sn-1”吧?

Sn=2an+Sn+?

问题题目不完整

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