当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值
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当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4
当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值
当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值
当x=3,y=7时,求分式(xy+2y)-(x+2)/x^2-4的值
(xy+2y)-(x+2)/x^2-4
=【y(x+2)-(x+2)】/(x+2)(x-2)
=(y-1)/(x-2)
=(7-1)/(3-2)
=6
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