已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1) 求M个位数是几
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/11 20:23:55
已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)求M个位数是几已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)
已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1) 求M个位数是几
已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1) 求M个位数是几
已知M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1) 求M个位数是几
M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2^16-1)(2^16+1)(2^32+1)(2^64+1)(2^128+1)
=(2^32-1)(2^32+1)(2^64+1)(2^128+1)
=(2^64-1)(2^64+1)(2^128+1)
=(2^128-1)(2^128+1)
=2^256 - 1
个位数 与2^4-1的个位数相同,为5
已知m*m+m-1=0,求m*m*m+2m*m-2005
数学已知m-1/m=2,则m²-1/m²=(),m+1/m=()已知m-1/m=2,则m²-1/m²=(),m+1/m=()大神速回
已知m+1/m=3,计算(m^4+m^2+1)/m^2的值
已知m^2+m-1=0,那么m^4+2m^3-m-2009=
已知m>4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3|
已知m^1/2+m^-1/2=4,求(m^3/2-m^-3/2)/(m^1/2-m^-1/2)=多少
已知m-(1/m)=3.则4-m平方/2+3m/2的值为?
已知m^2-5m-1=0,则2m^2-5m+(1/m^2)
已知m^2-5m-1=0,求2m^2-5m+(1/m)这道题能做吗
已知m²-5m-1=0 ,则2m²-5m+ (m²分之一)等于多少?
已知m=根号3,求(1-2m+m平方)/(m-1)-(m-1)/(m²-m)的值
已知m-1/m=3,m不等于0,求m^2-1/m^2,m^3-1/m^3,m^4-1/m^4
已知2m-5n=0,求(1+n/m-m/m-n)/(1-n/m-m/m+n)的值
若已知m^2-4m*3=1,求1-m^2+4m
已知m^2-5m-1=0,求(m^4+1)/m^2的值
已知m的平方-2m=1,求2m的平方-4m+2008
已知m²-2m=1,则2m²-4m+2013要原因
已知4|m+n|+4m^2+1=4m,求根号(m-n)^2.