已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?

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已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?已知实数a满足a²-a-1=0,则a八次方+7

已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?
已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?

已知实数a满足a²-a-1=0,则a八次方+7a负四次的值为?
a^2-a-1=0
a^2=a+1
a^4=(a+1)^2=a^+2a+1=3a+2
a^2-a=1
a-1=1/a
所以,原式=(3a+2)^2+7(a-1)^4
=9a^2+12a+4+7(a^2-2a+1)^2
=9a^2+12a+4+7(a+1-2a+1)^2
=9a^2+12a+4+7(a^2-4a+4)
=16(a^2-a+2)
=16(1+2)
=48