如图怎么化简
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如图怎么化简如图怎么化简 如图怎么化简 [sinB+sin(2π/3-B)]/sin(π/3)=2sin(B+π/6) [sinB+sin(2π/3)cosB-cos(2
如图怎么化简
如图怎么化简
如图怎么化简
[sinB+sin(2π/3-B)]/sin(π/3)=2sin(B+π/6)
[sinB+sin(2π/3)cosB-cos(2π/3)sinB]/(√3/2)=2sinBcos(π/6)+2cosBsin(π/6)
sinB+(√3/2)cosB+sinB/2=(2/√3)(√3sinB+cosB)
(√3/2)cosB+3sinB/2=2sinB+(2/√3)cosB
(√3/6)cosB=sinB/2
tanB=√3/3
所以B=π/6+kπ,k∈Z