新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>> A(:,1)=c*A(:,1)The following error occurred converting from sym to double:Error using ==> mupadmexError in MuPAD command:DOUBLE cannot convert the input expression into a double array.If

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新手matlabA=12335678910111213141516>>symsc;>>A(:,1)=c*A(:,1)Thefollowingerroroccurredconvertingfromsym

新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>> A(:,1)=c*A(:,1)The following error occurred converting from sym to double:Error using ==> mupadmexError in MuPAD command:DOUBLE cannot convert the input expression into a double array.If
新手 matlab
A =
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>> syms c;
>> A(:,1)=c*A(:,1)
The following error occurred converting from sym to double:
Error using ==> mupadmex
Error in MuPAD command:DOUBLE cannot convert the input expression into a double array.
If the input expression contains a symbolic variable,use the VPA function instead.
>>

新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>> A(:,1)=c*A(:,1)The following error occurred converting from sym to double:Error using ==> mupadmexError in MuPAD command:DOUBLE cannot convert the input expression into a double array.If
按照提示修改就行了,赋值类型错误了;不知道你的目的,A(:,1)=c*A(:,1)改为B=c*A(:,1)就可行了

新手 matlabA =1 2 3 35 6 7 89 10 11 1213 14 15 16>> syms c;>> A(:,1)=c*A(:,1)The following error occurred converting from sym to double:Error using ==> mupadmexError in MuPAD command:DOUBLE cannot convert the input expression into a double array.If 两个点之间的距离 matlaba=[3 4 8 9 3 4];b=[2];求b到a各点的距离·· 初学MATLAB,解线性方程程序请大家尽量把程序写长一些,程序越长越好,呵呵.1.求矩阵方程 x*(2 1 -1,2 1 0,1 -1 1)=(1 -4 3,4 3 2) 求出x的值,用MATLABA编出程序2.求线性方程组的解:2x1 - x2 -x3 +x4=2第一个方 reshape,permute函数matlabA = [1,2,3,4;5,6,7,8;9,10,11,12;13,14,15,16];如何得到B:B(:,:,1) = [1,2;5,6];B(:,:,2) = [3,4;7,8];B(:,:,3) = [9,10;13,14];B(:,:,4) = [11,12;15,16]; 将此矩阵对角的结果是什么MATLABa=[-4 -10 0 ;1 3 0; 3 6 1]将其对角化后是什么?eig和eigs得到的结果不一样啊eigs应该是对奇异矩阵有用的吧,但是手算出来的和eigs一样和eig不一样手算结果为-2,1,1eig算 matlab求极值问题1.如何用matlab求函数x^6+x^2-2x*y+y^3的极值,包括极大值与极小值2.如何用matlaba^+2b+^2c^2=1,求a+b+c^2的极值 求教 matlaba(2,2,2)=1;>> for i=1:2;for j=1:2;for k=1:2;a(i,j,k)=i+j+k;endendend运行显示:a(:,:,1) =3 44 5a(:,:,2) =4 55 6a(2,2,我的理解就是矩阵a在1维、2维、3维刻度为2相交的数值为1,但语言表述和最后的结果不是1 短时傅里叶变换程序,MATLABa=wavread('jiasiqi.wav');subplot(2,1,1),plot(a);title('original signal');gridN=256;h=hamming(N);for m=1:Nb(m)=a(m)*h(m)endy=20*log(abs(fft(b)))subplot(2,1,2)plot(y);title('短时谱');grid 数组乘方与矩阵乘方MATLABA =1 2 34 5 67 8 9>> A_Ap=A.^0.3A_Ap =1.0000 1.2311 1.39041.5157 1.6207 1.71181.7928 1.8661 1.9332>> A_Mp=A^0.3A_Mp =0.6962 + 0.6032i 0.4358 + 0.1636i 0.1755 - 0.2759i0.6325 + 0.0666i 0.7309 + 0.0181i 0.8292 - 0.0305i 问道新手问题1:现在是练什么属性角色比较好(灵 体 力)2:新手适合玩哪些区3:初级带什么宠物好 tanA=3,求2sinA-3cosA/2sinA+3cosA.新手. matlab新手A=1; a=-0.5; t=-2:0.01:2; if(t 中世纪2新手玩哪国好? 新手? 吉他 1=D 2=A 3=G 4=D 5=C T求具体我是新手渣 int b[ ][3]={{1},{3,2},{4,5,6},{0}};中b[2][2]的值为()我是新手,希望大家讲的详细一点, 当a=3,b=2,c=1时 表达式f=a>b>c的值为什么是0?新手提问, 设a1=5 an+1=2an+3^n(n≥1) 求an通项,我是新手啦.