x^2-2x-3
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x^2-2x-3x^2-2x-3x^2-2x-3=x^2-2x+1-1-3=(x-1)^2-4=(x-1-2)(x-1+2)=(x-3)(x+1)交叉相乘法得(x+1)(x-3)(x+1)(x-3)您
x^2-2x-3
x^2-2x-3
x^2-2x-3
=x^2-2x+1-1-3
=(x-1)^2-4
=(x-1-2)(x-1+2)
=(x-3)(x+1)
交叉相乘法得(x+1)(x-3)
(x+1)(x-3)
您好!答案为(x+1)(x-3)
交叉相乘法 1 1
1 -3
得到!希望可以帮到您!
求采纳!谢谢!
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