化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
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化简(1-sin^6a-cos^6a)/(cos^2a-cos^4a)==化简(1-sin^6a-cos^6a)/(cos^2a-cos^4a)==化简(1-sin^6a-cos^6a)/(cos^2
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
=[1-(sin²a+cos²)(sin^4a-sin²acos²a+cos^4a)]/cos²a(1-cos²a)
=[1-(sin^4a+2sin²acos²a+cos^4a)+3sin²acos²a]/cos²asin²a
=[1-(sin²a+cos²a)²+3sin²acos²a]/cos²asin²a
=3cos²asin²a/cos²asin²a
=3
(1-sin^6 a-cos^6 a)/(sin^2 a-sin^4 a) 请放心使用,有问题的话请追问 满意请及时采纳,谢谢,采纳后你将获得5财富值。 你的采纳将是我继续努力帮助他人的最强动力!
=[1-(cos^6 a+sin^6 a)]/(sin^2 a-sin^4 a)
=[1-(cos^2a+sin^2a)(cos^4a-sin^2a*cos^2a+sin^4a)]/sin^2a(1-sin^2a)
=(1-cos^4a+sin^2a*cos^2a-sin^4a)/(sin^2a*cos^2a)
=[(1-cos^2a)(1+cos^2a)+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=[sin^2a+sin^2acos^2a+cos^2asin^2a-sin^4a]/(sin^2a*cos^2a)
=3sin^2acos^2a/(sin^2a*cos^2a)
=3
化简1-sin^4a-cos^4a/1-sin^6a-cos^6a
1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简:(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)
化简1-cos^4a-sin^4a/1-cos^6-sin^6acos^6应为cos^6a
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?急用!
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?急用!
化简[1-cos^4(A)-sin^4(A)]/[1-cos^6(A)-sin^6(A)] 等于多少?急用!
(1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=?
(1-sin^4a-cos^4a)/(1-sin^6a-cos^6a)
化简tan a(cos a-sin a)+sin a(sin a+tan a)/1+cos a
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
Sina+sin^2a=1,cos^2a+cos^s4a+cos^6a
当sinˆa+sin^2a=1求cos^+cos^6的值
=1-(sin^6a+cos^6a) ------(1)=1-(sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------(2)由(1)怎么能到(2)呢=1-(sin^6a+cos^6a)=1-(sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a)