将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式
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将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式sinx
将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式
将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式
将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式
sinx+siny+sinz-sin(x+y+z)=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]
sinx+siny+sinz-sin(x+y+z)
=2sin[(x+y)/2]cos[(x-y)/2]+sinz-sin(x+y)cosz-sinzcos(x+y)
=2sin[(x+y)/2]cos[(x-y)/2]+sinz[1-cos(x+y)]-sin(x+y)cosz
=2sin[(x+y)/2]cos[(x-y)/2]+2sinz*sin[(x+y)/2]^2-2sin[(x+y)/2]cos[(x+y)/2]cosz
=2sin[(x+y)/2]*{cos[(x-y)/2]+sinzsin[(x+y)/2]-cos[(x+y)/2]cosz}
=2sin[(x+y)/2]*{cos[(x-y)/2]-cos[z+(x+y)/2]}
=2sin[(x+y)/2]*2sin[(x+z)/2]sin[(y+z)/2]
=4sin[(x+y)/2]sin[(x+z)/2]sin[(y+z)/2]
将sinx＋siny＋sinz－sin（x＋y＋z）化为积的形式
将sinx+siny+sinz-sin(x+y+z)化为积的形式
m=(sinx)/sin(y-z),n=(siny)/sin（z－x）,p=（sinz）/sin（x－y）,求mn+np+pm.
三角不等式证明证明sin(x+y)+sin(y+z)+sin(z+x)>sinx+siny+sinz+sin(x+y+z)
证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2)
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|sinx-siny|
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