For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next ivb for循环中计算s 的值
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Fori=2.6To4.9Step0.6s=s+1Nextivbfor循环中计算s的值Fori=2.6To4.9Step0.6s=s+1Nextivbfor循环中计算s的值Fori=2.6To4.9S
For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next ivb for循环中计算s 的值
For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next i
vb for循环中计算s 的值
For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next ivb for循环中计算s 的值
若S初值为0,此循环总共被执行3次,执行结束后,S=3!
在 for i= 2.6 to 4.9 step 0.6 里面,初值是2.6,2.6开始循环,到4.9终止,每一步的步长是0.6.所以：
第一次,i= 2.6 S=0+1 S=1
第二次,i= 3.2 S=1+1 S=2
第三次,i= 4.4 S=2+1 S=3
第四次,i= 5.0 循环体不执行,转向Next跳出.
s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i
For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next ivb for循环中计算s 的值
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