s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i

s=5 for i 2.6 to 4.9 step 0.6 s=s+1 next i 是怎样解的啊s=5for i 2.6 to 4.9 step 0.6 s=s+1 next i s=1 for i=1 to 5 step 2 s=s+i endfor s For i = 2.6 To 4.9 Step 0.6 s = s + 1 Next ivb for循环中计算s 的值 VB执行下列程序：S=5 For I = 2.6 to 4.9 step 0.6 S = S + 1 Next i Print S 求程序运行后的结果! dim I% ,S% s=0 for I=5 to 1 s=s+i next I print “s=” ; s 怎么看的 dim I% ,S%s=0for I=1 to 5 step -1s=s+inext Iprint “s=”;s 还有这个一起求解释~ s=20 For i=1 to 5 setp2 S=S-i Next i print S 到底怎么个算法? s=0,for i=1 to 5,for j=1 to i,for k=j to 4,s=s+1,next k,next j,next i,msgbox s,求详解s= 0For i = 1 To 5For j = 1 To iFor k = j To 4 s = s + 1Next k Next j Next iMsgBox sA.4 B.5 C.38 D.40自己算的和四个选项都不一样. VB编程 s=5 for i=1 to 23step6 s=s+1 next i 执行程序,为啥i的值为25? s=1 for i=1 to 100 s=s*i endfor s 中的s=1 和s=s*i free pascal 马鞍数c:array[1..5,1..5] of integer; i,n,y,s:integer;begin y:=0; for n:= 1 to 5 do for i:= 1 to 5 do read (c[n,i]); for n:=1 to 5 do for i:=1 to 5 do begin for s:= 1 to 5 do begin if c[n,i] <= c[n,s] and c[n,i] >= c[s,i] then y:= Dim a(4) s=0 For i=1 to 4 s=s+a(i) Next i s = 2 For i = 3.2 To 4.9 Step 0.8 s = s + 1 next i求运行结果为什么 麻烦解释下咯 vb题 s=0:n=5 for i=1 to n s=s+i next i print s;i 结果怎么是15 i怎么不是5啊 pascal编程s=1+3+5+...+n,求s.var s,n,i:integer;beginreadln(n);for i:=1 to ______ doif ______________then s:=s+i;writeln(s);end. set talk offdime a(7)use xsdas=0for i=3 to 5scatter to as=s+a(7)skipendfors=+str(s)return free pascal中for语句的具体意思.比如 for i=1 to 100 do s=s+free pascal中for语句的具体意思.比如for i=1 to 100 do s=s+i 14.有如下的Visual Basic程序段：s = 1 For i = 10 To Step -1 s = s * i * (i14.有如下的Visual Basic程序段：s = 1For i = 10 To Step -1s = s * i * (i - 1)Next i若要使语句s = s * i * (i - 1)执行5次,则循环变量i终值应为（A （1）设有如下的Visual Basic表达式：5 * x^2 - 3 * x - 2 * Sin(a)/3 它相当于代数式【1】 .（2）执行下面的程序段后,s的值为 【2】 .s = 5 For i = 2.6 To 4.9 Step 0.6 　s = s+1 Next i （3）在窗体上画一个命令