X-Y=4,X^2-y^2=12.则XY等于?
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X-Y=4,X^2-y^2=12.则XY等于?X-Y=4,X^2-y^2=12.则XY等于?X-Y=4,X^2-y^2=12.则XY等于?x²-y²=(x+y)(x-y)即:12=
X-Y=4,X^2-y^2=12.则XY等于?
X-Y=4,X^2-y^2=12.则XY等于?
X-Y=4,X^2-y^2=12.则XY等于?
x²-y²=(x+y)(x-y)
即:12=4(x+y)
得:x+y=3
x+y=3
x-y=4
两式相加得:2x=7,则:x=7/2
所以,y=-1/2
所以,xy=-7/4
由x^2-y^2=(x+y)(x-y)=4(x+y)=12,得x+y=3.又x-y=4,故x=7/2,y= -1/2,xy=-7/4.
x^2-y^2=12
即(x+y)(x-y)=12
且x-y=4
那么x+y=3
解得x=3.5
y=-0.5
xy=-7/4
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