将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是A.Na2SO4和BaCl2 B.BaCl2和CaCO3 C.Ba(NO3)2和Na2SO4 D.B

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将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是A.Na2SO4和BaCl2B.BaCl2和CaCO3C.B

将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是A.Na2SO4和BaCl2 B.BaCl2和CaCO3 C.Ba(NO3)2和Na2SO4 D.B
将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是
A.Na2SO4和BaCl2 B.BaCl2和CaCO3 C.Ba(NO3)2和Na2SO4 D.BaCl2和Na2SO4

将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是A.Na2SO4和BaCl2 B.BaCl2和CaCO3 C.Ba(NO3)2和Na2SO4 D.B
选D
A中含氯离子,B中含硫酸根离子,所以A是氯化钡,B是硫酸钠.

D

D.BaCl2和Na2SO4

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将硝酸银溶液滴入盐A的溶液中,产生不溶于稀硝酸的白色沉淀.将钠盐B的溶液滴入盐A的溶液中也产生不溶于稀硝酸的白色沉淀.则A和B的化学式分别是A.Na2SO4和BaCl2 B.BaCl2和CaCO3 C.Ba(NO3)2和Na2SO4 D.B 气体X可能含有NH3、Cl2、HBr、CO2中的一种或几种.将X通入硝酸银溶液产生不溶于稀硝酸的浅黄 某物质加入硝酸银或硫酸钠溶液都会产生不溶于硝酸的白色沉淀,该物质是?A.盐酸B.碳酸钠溶液C.硝酸钡溶液D.氯化钡溶液帮我解释下原因... 融入硝酸银溶液中,可生成不溶于稀硝酸的黄色沉淀的气体 将硝酸银溶液滴加到食盐溶液中 请给出问题分析.X为氨气、氯气、硫化氢、溴化氢、二氧化碳中的一种或几种,将其通入硝酸银溶液中产生淡黄色不溶于稀硝酸的沉淀,X通入澄清石灰水中无沉淀,关于X:A.一定有溴化氢,一定有 往无色溶液中滴加硝酸银溶液产生不溶于稀硝酸的白色沉淀,则些无色溶液中 ( ).A.一定含有硫酸根离子 B.一定含有氯离子C.只有硫酸根离子,没有氯离子 D.可能含有硫酸根离子或氯离子, 往无色溶液中滴加硝酸银溶液产生不溶于稀硝酸的白色沉淀,则些无色溶液中 ( ).A.一定含有硫酸根离子 B.一定含有氯离子C.只有硫酸根离子,没有氯离子 D.可能含有硫酸根离子或氯离子, 某溶液中加入Bacl2溶液,产生不溶于硝酸的白色沉淀,该溶液一定含有Ag+ 某溶液中加入氯化钡溶液后,生成不溶于稀硝酸的白色沉淀,则此溶液是 A稀硫酸 B硫酸钠 C硝酸银 D以上都不对我怎么认为以上都对呢? 化学检验选择 一道A.某溶液与NaOH溶液共热,产生能使湿润的蓝色石蕊试纸变红的气体,说明原溶液中存在铵根离子B.某溶液中加入硝酸银溶液时,产生白色沉淀,加稀硝酸沉淀不溶解,说明原溶 配制硝酸银溶液时将硝酸银固体先溶于较浓的硝酸中然后在用蒸馏水稀释到所需的浓度 检验火柴头中含有的铝元素,可将3-4跟火柴头摘下,浸泡在水中,然后取少量溶液于试管中,接下来需要滴加的试剂是A硝酸银溶液和稀硝酸B硝酸银溶液C硝酸银溶液、稀硝酸和亚硝酸钠溶液D三氧 加入硝酸银溶液生成的白色沉淀不溶于稀硝酸的溶液中一定有氯离子吗?如果硫酸银就是那白色沉淀,那请问是什么溶液和硝酸银生成硫酸银呢 为什么硝酸银溶液和稀硝酸,若产生白色沉淀且不溶于稀硝酸,则是氯离子..主要的是为什么说不用于稀硝酸! 在无色溶液中,加入氯化钡,无现象,再加入硝酸银,产生不溶于硝酸的白色沉淀,为什么原溶液中有氯离子之前加入氯化钡的时候就引入了氯离子,那溶液中的氯离子为什么会有原溶液的呢 将B溶液和C溶液混合产生白色沉淀,白色沉淀不溶于酸.将A溶液和D溶液混合产生白色沉淀,同时有气体产生将A溶液和B溶液混合产生白色沉淀,同时有气体产生已知ABCD四种物质由阳离子:钠离子 有一种不溶于水的白色晶体A,加入盐酸后能产生无色无味的气体B…………B能使澄清石灰水变浑浊,再滴入稀硫酸生成不溶于稀硝酸的白色沉淀C,然后过滤,再滤液中加入硝酸银溶液,又生成不溶