1/48+1/80+1/120+1/168

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1/48+1/80+1/120+1/1681/48+1/80+1/120+1/1681/48+1/80+1/120+1/1681/48+1/80+1/120+1/168=1/(6*8)+1/(8*10

1/48+1/80+1/120+1/168
1/48+1/80+1/120+1/168

1/48+1/80+1/120+1/168
1/48+1/80+1/120+1/168
=1/(6*8)+1/(8*10)+1/(10*12)+1/(12*14)
=1/6-1/8+1/8-1/10+1/10-1/12+1/12-1/14
=1/6-1/14
=2/21

1/48=1/2*(1/6-1/8)
1/80=1/2*(1/8-1/10)
1/120=1/2(1/10-1/12)
1/168=1/2(1/12-1/14)

1/48+1/80+1/120+1/168
=1/2 *(1/6-1/14)
=1/2 *4/42
=2/42
=1/21

1/48+1/80+1/120+1/168
=（1/2）[（1/6-1/8）+（1/8-1/10）+（1/10-1/12）+（1/12-1/14）]
=（1/2）[1/6-1/14]
=（1/2）（7-3）/14
=1/7

=1/48+3/240+2/240+1/168
=1/48+5/240+1/168
=1/48+1/48+1/168
=1/24+1/168
=21/504+3/504
=1/21

1/48+1/80+1/120+1/168 (1/8+1/24+1/48+1/80+1/120+1/168+1/224)*64= (1/8+1/24+1/48+1/80+1/120+1/168+1/224)乘64 (1/8+1/24+1/48+1/80+1/120+1/168)简便计算 （1/8+1/24+1/48+1/80+1/120+1/168）乘以56 （8/1+24/1+48/1+80/1+120//1+168/1）*42 1/8+1/24+1/48+1/80+1/120+1/168 （1/8+1/24+1/48+1/80+1/120+1/168）*56 42x(8/1+24/1+48/1+80/1+120/1+168/1)=?求求 42X（1/8+1/24+1/48+1/80+1/120+1/168）求解 8分之1+24分之1+48分之1+80分之1+120分之1=? 8/1+24/1+48/1+80/1+120/1要过程 121x3/4-3/8x40-0.75(1/8+1/24+1/48+1/80+1/120+1/168)x56(7-11/16x3)+(1-11/16x7)+(5-11/16)+(3-11/16x5) 计算 （80+120）*（1+16%)=80*(1-5%)+120*(1+x) 计算：（1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/288)*128 (1/8+1/24+1/48+1/80+1/120+1/168+1/224+1/288)*128 简算:(8/1+24/1+48/1+80/1+120/1+168/1+224/1+288/1)×128 （8/1+24/1+48/1+80/1+120/1+168/1+224/1+288/1）*128