化简la-bl+la+bl=lc-al-lc-bl

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化简la-bl+la+bl=lc-al-lc-bl化简la-bl+la+bl=lc-al-lc-bl化简la-bl+la+bl=lc-al-lc-blla-bl+la+bl=lc-al-lc-bl≤l

化简la-bl+la+bl=lc-al-lc-bl
化简la-bl+la+bl=lc-al-lc-bl

化简la-bl+la+bl=lc-al-lc-bl
la-bl+la+bl=lc-al-lc-bl≤lc-a-(c-b)l=lb-al
所以必然有a=b且c-a=±a
所以a=b,且c=0
或a=b,且c=2a