tana=1/3,sin^2-sinacosa-cos^2a=?tana=1/3,sin^2-sinacosa-cos^2a=?详细写出思路

已知1+tana/1-tana=2,求2sin^2-3sinacosa tana/2+tana/2=5/2,求sin(a-pai/3)1 tana=1/3则2sin平方-sinacosa= 若1+sin^2=3sinacosa,求tana 求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana tanA=2 求(sin^2 A+ sinAcosA)/(tanA+1+sin^2 A) 急 . sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=? sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=? 已知sin(a+b)=1/2,sin（a-b)=1/3,求tana/tanb 已知sin(a+x)=1/2,sin(a-x)=1/3,则tana/tanx 已知sin(A+B)=2/3,sin(A-B)=1/5.求tanA/tanB 已知sin(a+b)等于2/3,sin(a-b0 =1/5,求tana:tanb sin^2A+cos^2A/sinAcosA=-10/3怎么得到 tanA+1/tanA=-10/3 tana=1/3,sin^2-sinacosa-cos^2a=?tana=1/3,sin^2-sinacosa-cos^2a=?详细写出思路 (1+tanA )/1-tanA=3+根2 求cos平方(pai-A)+sin(pai+A)*cos(pai-A)+2sin平方（A-3pai) 已知(1+tana)/(1-tana)=3+2√2,求cos(π-a)方+sin(π+a)cos(π-a)+sin(a-π)方 已知tana/tana-1=-1 求 sin(PAI-A) +3cos(PAI +a)/sina +cos (-a) 和sin ^2 +sinacosa +2 已知锐角△ABC中,sin(A+B)=3/5,sin(A-B)=1/51求证tanA=2tanB2求tanA的值