已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2B=sin^2C
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 10:35:12
已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2B=sin^2C已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2
已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2B=sin^2C
已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2B=sin^2C
已知:sin^2A/sin^2B+cos^2Acos^2C=1,求证:tan^2Acot^2B=sin^2C
因为cos^2C=(1-sin^2A/sin^2B)/cos^2A
所以sin^2C=1-(1-sin^2A/sin^2B)/cos^2A
=1+sin^2A/(sin^2B*cos^2A)-1/cos^2A
=(sin^2B*cos^2A+sin^2A-sin^2B)/(sin^2B*cos^2A)
=[(1-cos^2B)*(1-sin^2A)+sin^2A-1+cos^2B]/(sin^2B*cos^2A)
=(sin^2A*cos^2B)/(sin^2B*cos^2A)
=tan^2Acot^2B
所以等式成立
已知sin(a+b)sin(a-b)=-1/3,求cos^2a-cos^2b的值
已知sin(a+b)sin(b-a)=m,试求cos^2a-cos^2b的值
证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1
化简sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b
sin^2a+sin^2b-sin^2a * sin^2b+cos^2a * cos^2b 化简
sin^2 (A)+sin^2(B)-sin^2(A)sin^2(B)+cos^2(A)cos^2(B)
化简cos(a+b)cos(a-b)+sin^2b
已知sin^4a/cos^2b+cos^4a/sin^2b=1,求证:sin^4 b/cos^2 a+cos^4b/sin^2a=1
已知(cos^4a)/cos^2b+(sin^4a)/sin^2b=1求证(cos^4b)/cos^2a+(sin^4b)/sin^2a=1
化简(sin(a-b)-2sin a cos b)/2sin a sin b +coa(a+b)
已知 sin a,sin 2x ,cos a 成等差数列,sin a ,sin x ,cos a 成等比数列,求cos 2x 的值.已知 ,3sin^2 a+2sin^2 b=1 ,3sin 2a-2sin 2b=0 且a ,b 为锐角,试求 a+2b的值.
已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x
已知sin a+sin b=1/2,cos a+cos b=(根号3)/2,求证:sin(a+TT/3)=1/2
已知cosB = cos θ*sinA,cosC = sinθ*sinA.θ为已知角.则sin^2 A + sin^2 B +sin^2C等于多少?
(1/2)已知向量a=(cos阿尔法,sin阿尔法),向量b=(cos贝塔,sin贝塔),其中0
已知tan a=2,求sin a+cos a /cos a -sin a 的值
cos^2a-cos^2b=m,那么sin(a+b)sin(a-b)=?
证明sin(A+B)sin(A-B)=cos^2B-cos^2A