数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 23:34:18
数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?数列{an},a1=
数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?
数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?
数列{an},a1=1,an+1(n+1为下标)=n/(n+1)an则{an}通项公式为?
a(n+1)/an=n/(n+1)
所以有:
an/a(n-1)=(n-1)/n
a(n-1)/a(n-2)=(n-2)/(n-1)
………………………………
a3/a2=2/3
a2/a1=1/2
以上各式左右分别相乘,分别抵消:
左式=an/a1=an;右式=1/n
an=1/n
a(n+1)=n/(n+1)an
an=(n-1)/n a(n-1)
a(n-1)=(n-2)/(n-1)a(n-2)
...........
a(4)=3/4a3
a(3)=2/3a2
a(2)=1/2a1=1/2
a(n+1)=n/(n+1)* (n-1)/n * (n-2)/(n-1) * .....3/4*2/3*1/2
=1/(n+1)
则an=1/n
将an除过去再用连乘法 仔细想想
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
数列{an}中,a1=1,an+1/an=n/n+2,求an
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?
已知数列{an}满足an+1=an+n,a1等于1,则an=?
数列{an}中,a1=35,an+1-an=2n-1,求an
已知数列an,a1=1 an+1-an=2的n次幂求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an集合中,a1=2,an+1=an+(2n+1),求an.
已知数列an中,a1=1,an+1=an+n,求an
数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标
在数列an中,a1=2 an+1=an+3n则an=
数列an,a1=4,an+1=5^n*an,求an用累乘法
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
已知数列{An}中,a1=4,an+1+an=6n+3,求证数列an-3n是等比数列,求证数列an的通项an
已知数列{an}满足a(n+1)=an+n,a1=1,则an=
数列an满足a1=1/3,Sn=n(2n-1)an,求an