已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10
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已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10已知数列{an}满足a1=2,an=a(n+1)-2,求an及S
已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10
已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10
已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10
a(n+1)-an=2
而a2=a1+2 所以a2=4 a3=6
所以为等差数列 an=2n
sn=n×n+n
s10=110
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