x+2x=y+3y=40+x+y
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x+2x=y+3y=40+x+yx+2x=y+3y=40+x+yx+2x=y+3y=40+x+y把他拆成3个方程组,两两组合.x+2x=y+3y,得3x-4y=0(1)y+3y=40+x+y,得3y-
x+2x=y+3y=40+x+y
x+2x=y+3y=40+x+y
x+2x=y+3y=40+x+y
把他拆成3个方程组,两两组合.
x+2x=y+3y,得3x-4y=0 (1)
y+3y=40+x+y,得3y-x=40 (2)
(2)*3+(1):5y=120,y=24
3x-4y=0,x=32
移项,分解成两个方程
x+2x-y-3y=0 即3x-4y=0
x+y+40=y+3y x-3y=-40
解得x=32
y=24
望采纳 谢谢
∵3x=40+x+y
∴y=2x-40
又3x=4y=4(2x-40)
∴3x=8x-160
5x=160
x=32
∴y=2x-40
=64-40
=24
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