Matlab syms a b c x1 x2 x3 x4 x5 y1 y2 y3 y4 y5 z1 z2[a,b,c,x1,x2,x3,x4,x5,y1,y2,y3,y4,y5,z1,z2]=solve('z1cos(a+b*1.867-c)=x1','z2cos(a+b*1.867-c)=y1','x1+y1=0.22','z1cos(a+b*9.15-c)=x2','z2cos(a+b*9.15-c)=y2','x2+y2=-0.284','z1cos(a+b*16.37-c)=x3','

Matlab syms a b c x1 x2 x3 x4 x5 y1 y2 y3 y4 y5 z1 z2[a,b,c,x1,x2,x3,x4,x5,y1,y2,y3,y4,y5,z1,z2]=solve('z1cos(a+b*1.867-c)=x1','z2cos(a+b*1.867-c)=y1','x1+y1=0.22','z1cos(a+b*9.15-c)=x2','z2cos(a+b*9.15-c)=y2','x2+y2=-0.284','z1cos(a+b*16.37-c)=x3',' MATLAB定义多个符号变量我知道定义几个的时候syms a b c t;%定义多个符号变量但是定义比较多,例如我有x1,x2,.x100个变量这时该怎么定义呢? matlab解符号方程syms a b c d;f1=a +b+c+d;f2=2*a+4*d+3*c+5*d;f3=4*a+b+3*c+2*d;f=solve(f1,f2,f3) 结果为f = b: [1x1 sym] c: [1x1 sym] d: [1x1 sym] 默认是用a来表示b c d的.但是我想用d来表示a b c,应该怎么办? matlab 解方程组 总是返回1*1 sym.输入内容：syms a b c e2 e3 e4;I=a^2/2+6/5*a*b+4/3*a*c+3/4*b^2+12/7*b*c+c^2-(e2*a+e3*b+e4*c);x=diff(I,a);y=diff(I,b);z=diff(I,c);S=solve(x,y,z,a,b,c)输出：S =a:[1x1 sym]b:[1x1 sym]c:[1x1 sym]我想得出 如何用Matlab画含积分函数式子的图形syms x1 Q_N;p = 125; w = 80; w2 = 85; c = 35; c2 = 50; v = 20; h = 10; a = 130; b = 1;rate = [10 12 28 22 18 10];demand = 5500:200:6500;r = sum(rate); AVG = rate * demand'/r matlab程序运行总是出现? Error using ==> sym.mpower Matrix must be square. 加了“.”还是不行呀m=zeros(1,50);a=zeros(1,50);b=zeros(1,50);f0=zeros(1,50); syms d x1 x2 e; m(1)=1;c= matlab syms 运行出错>> syms x a b c f=sym('a*x^2+b*x+c')findsym(f,4)y(1)=limit(f,x,1)y(2)=limit(f,1)y(3)=limit(f,a,2)y(4)=limit(f,b,1)yAttempt to execute SCRIPT syms as a function.Error in ==> jixian at 1syms x a b c 请问是为什么呢? matlab 最速下降法求解clc;clear;disp('最速下降法')syms x1 x2 lam;x=[x1 x2];t=0; X0=[1;1]; y=(x1^2+x2-11)^2+(x1+x2^2-7)^2;e=0.01;for n=1:10 a=subs(diff(y,x1),x,X0); b=subs(diff(y,x2),x,X0); yj=[a;b]; z=subs(y,x,X0-lam*y matlab 程序出错syms a b c;M1=sym('kiu');M2=sym('kog');M3=sym('lou');syms_matrix=syms_matrix=[a b c;M1,M2,M3;int2str([2 3 5])] matlab中我想用输入t表示一个数来计算二次方程的交点啊?clccleart=input('t=?');syms x yeq1=(x-14-t)^2+(y-290)^2-160^2=0;eq2= x^2+y^2-190^2=0 ;[x,y]=solve(eq1,eq2)a=vpa(x(1),10)b=vpa(x(2),10)c=vpa(S.y(1),10)d=vpa(S.y(2),10)x1=min(dou Matlab出现内部矩阵维度不一致?x1=1:10:100;a=46+0.12*x1+((6-0.12*x1).^2*(46+0.12*x1))./(36-(6-0.12*x1).^2);b=(10-0.3*x1)*x1;c=25-1.8*((6-0.12*x1)*(46+0.12*x1))./(36-(6-0.12*x1).^2);y=7./64*a.^2+b+c;plot(x1,y);在matlab中怎么算不出来, MATLAB 中syms 7A+18.2B+43.03C=48.7918.2A+45.03B+190.472C=144.66143.03A+190.472B+677.8756C=488.9851syms x1 x2 x3 f1=7*x1+18.2*x2+43.03*x3=48.79;f2=18.2*x1+45.03*x2+190.472*x3=144.661;f3=43.03*x1+190.472*x2+677.8756*x3=488.9851;[x1,x2,x3]=solve(f1,f2,f3)直接在mat matlab中用循环绘制a与c的关系曲线.求大神相助,急用啊.syms a cfor a=10:5:30x1=0:0.001:a/2y1=3*x1+1x2=a/2:0.001:ay2=-3*x2+10[y1_max]=max(y1)[y2_max]=max(y2)c=max([y1_max,y2_max])plot(a,c)end其中c表示在不同a的取值时,函数y1 matlab初学者,麻烦给解个三角函数的方程,我的怎么没有解呀?syms a b c>> [a,b,c]=solve('cos(a)*sin(b)*cos(c)+sin(a)*sin(c)=0.2082','sin(a)*sin(b)*cos(c)-cos(a)*sin(c)=0.71937','cos(b)*cos(c)=0.6691') matlab 如何画圆syms a b;ezplot( (2-a).^2+(50-b).^2 );为什么这样画只能出现一个点?不能出现一个圆syms a b;ezplot( (2-a).^2+(50-b).^2-1 );这样子也不可以 matlab中syms类型画图,小白如何画出图形并标出极值点syms a b; >> fi=(1600*cot(b)*(1+1/sin(b)))/240+((1/cos((a-b)/2))*(1600-1600*cot(b)*cot(b)) Matlab syms a b c d[a,b,c,d,]=solve('cos(a+b+c*d)=5','cos(a+b-c*d)=6','cos（a-b+c*d）=7','cos(a+b+c/d)=8')这是Matlab程序,为什么说我Error using ==> solve at 77' cos（a-b+c*d）=7 ' is not a valid expression or equation.错在哪?急