已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 13:03:29
已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是已知tan(x+y)=2/5,tan(x-y)=
已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是
已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是
已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是
tan2x=tan [(x+y)+(x-y)]
=[tan(x+y)+tan(x-y)]/[1-tan(x+y)tan(x-y)]
=3/22
已知tan(x-y)=2,tan(y+π/5)=3,则tan(x+π/5)等于
已知tan(x-pi/6)=3/7,tan(y+pi/6)=2/5,则 tan(x+y)=?
求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y
1 求证:tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)2 已知a+b+c=npai(n属于Z),求证:tan(a)+tan(b)+tan(c)=tan(a)tan(b)tan(c)(提示:在等式a+b=npai-b同时取正切)
已知sin(2x+y)=5siny,(y不等于K派),求证;3tan=2tan(x+y)
已知tan(x+y)=3,tan(x-y)=5则tan2x等于
求证tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-a)tan(z-x)
已知tan(x+y)=2/5,tan(x-y)=-1/4,则tan2x的值是
tan(x+y)=
y=tan 2x/tan x 的定义域是什么?y=tan 2x/tan x 的定义域是什么?
若tan(2x+y)=3,tanx=5,则tan(x+y)等于多少
已知5siny=sin(2x+y),求证:tan(x+y)=3/2tanx
求证tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)tan(x-y)+tan(y-z)怎么化成tan〔(x-y)+(y-z)〕?
若tan(x)=4tan(y),求x,y关系 (已知0
若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
5cos(x-y/2)+7cos(y/2)=0求tan(x/2)*tan[(x-y)/2]
证明tan(x+y)+tan(x-y)=sin2x/cos^2x-sin^2y
已知函数y=(tanx-tan^3 x)/(1+2tan^2 x+tan^4 x)的最大值与最小值的积为