求极限lim(x→0)((1+x)^1/2)-1/sinx
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求极限lim(x→0)((1+x)^1/2)-1/sinx求极限lim(x→0)((1+x)^1/2)-1/sinx求极限lim(x→0)((1+x)^1/2)-1/sinxlim(x→0)((1+x
求极限lim(x→0)((1+x)^1/2)-1/sinx
求极限lim(x→0)((1+x)^1/2)-1/sinx
求极限lim(x→0)((1+x)^1/2)-1/sinx
lim(x→0)((1+x)^1/2)-1/sinx
=lim(x→0)[(1+x)^(1/2)-1]'/(sinx)'
=lim(x→0){1/2[(1+x)^(1/2)]}/cosx
=[1/2(1+0)^(1/2)]/cos0
=1/2.
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