(1)2/x-1+x+1/1-x (2)x+3/3-x+x²-9/x²+6x+9 (3)a+2-4/2-a

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(1)2/x-1+x+1/1-x(2)x+3/3-x+x²-9/x²+6x+9(3)a+2-4/2-a(1)2/x-1+x+1/1-x(2)x+3/3-x+x²-9/x&

(1)2/x-1+x+1/1-x (2)x+3/3-x+x²-9/x²+6x+9 (3)a+2-4/2-a
(1)2/x-1+x+1/1-x (2)x+3/3-x+x²-9/x²+6x+9 (3)a+2-4/2-a

(1)2/x-1+x+1/1-x (2)x+3/3-x+x²-9/x²+6x+9 (3)a+2-4/2-a
(1)2/x-1+x+1/1-x
=2/(x-1)-(x+1)/(x-1)
=(2-x-1)/(x-1)
=(1-x)/(x-1)
=-1
(2)x+3/3-x+x²-9/x²+6x+9
=(3+x)/(3-x)+(x-3)(x+3)/(x+3)²
=(3+x)/(3-x)-(3-x)/(3+x)
=[(3+x)²-(3-x)²]/(3-x)(3+x)
=12x/(9-x²)
(3)a+2-4/2-a
=(a+2) +4/(a-2)
=(a²-4+4)/(a-2)
=a²/(a-2)