x+y+z=110 x=y+z-8 y=z+13 用三元一次方程组解..步骤都要..不要漏步骤

(x+y-z)(x-y+z)= X+Y+Z=? x/y=(x+z)/(y+z)y/z=(x+y)/(x+z) 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? (y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值 x+y=8 y+z=12 x+z=10 x+y+z= x+y=8 y+z=12 x+z=10 x+y+z= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z x=y; y=z; z=x/y 用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证? z+=x>y?++x: fangchengzu:X+Z=Y 7Z=X+Y+Z X+Y+Z=14 (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是 （y+z-2x)(x-2y+z)分之（x-z)(y-z) 若X/10=Y/8=Z/9则X+Y+Z/Y+Z=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 已知x>0 y>0 z>0 求证 (y/x+z/x)(x/Y+z/y)(x/z+y/z)>=8如题. 已知x>0,y>0,z>0.求证（y/x+z/x）（x/y+z/y)(x/z+y/z）>=8