(x-2)(x-4)-(x-1)(x-5)求过程
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(x-2)(x-4)-(x-1)(x-5)求过程(x-2)(x-4)-(x-1)(x-5)求过程(x-2)(x-4)-(x-1)(x-5)求过程=x^2-6x+8-x^2+6x-6=2=X2-6X+8
(x-2)(x-4)-(x-1)(x-5)求过程
(x-2)(x-4)-(x-1)(x-5)求过程
(x-2)(x-4)-(x-1)(x-5)求过程
=x^2 -6x +8 -x^2 +6x -6
= 2
=X2-6X+8-X2-6X-5
=3
=x^2 -6x +8 -x^2 +6x -5
= 3 你应该总结下怎么去括号。的
还有一种方法是:
(x-2)(x-4)
=[(x-1)-1][(x-5)+1]
=(x-1)(x-5)+x-1-x+5-1
=(x-1)(x-5)+3
可以看出前者比后者大3,所以前者大。
当然,如果本题是一道选择题,无需以上步骤,直接取x=0,代入计算就可知道前者比后者大。
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