2/（x+1）≤1解不等式
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2/（x+1）≤1解不等式2/（x+1）≤1解不等式2/（x+1）≤1解不等式解不等式2/(x+1)≤1[2/(x+1)]-1=(-x+1)/(x+1)=-(x-1)/(x+1)≤0,即(x-1)(x
2/（x+1）≤1解不等式
2/（x+1）≤1解不等式
2/（x+1）≤1解不等式
解不等式2/(x+1)≤1
[2/(x+1)]-1=(-x+1)/(x+1)=-(x-1)/(x+1)≤0,即(x-1)(x+1)≧0,
故得x
由题可得 2≤x+1
移项得 x≥1
∴﹣2