lim(x→∞,y→∞) x+y/x^2-xy+y^2
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/26 14:45:26
lim(x→∞,y→∞)x+y/x^2-xy+y^2lim(x→∞,y→∞)x+y/x^2-xy+y^2lim(x→∞,y→∞)x+y/x^2-xy+y^2因x^2+y^2≥2|xy|,所以0≤|(x
lim(x→∞,y→∞) x+y/x^2-xy+y^2
lim(x→∞,y→∞) x+y/x^2-xy+y^2
lim(x→∞,y→∞) x+y/x^2-xy+y^2
因x^2+y^2≥2|xy|,所以
0≤|(x+y)/(x^2-xy+y^2)|
≤|x+y|/(x^2+y^2-|xy|
≤|x+y|/|xy|
≤1/|x|+1/|y|
且lim(1/|x|+1/|y|)=0
故lim[(x+y)/(x^2-xy+y^2)]=0.
0≤|(x+y)/(x^2-xy+y^2)| ≤|x+y|/(x^2+y^2-|xy| ≤|x+y|/|xy| ＝1/|x|+1/|y|
因x→∞,y→∞，lim(1/|x|+1/|y| )=0
由夹逼原理，极限是零
lim(x→∞,y→∞) x+y/x^2-xy+y^2
求极限lim(x→+∞,y→+∞) (X+Y)/(X^2-Y^2)
lim(x→∞,y→∞) x+y/x^2-xy+y^2
lim(x→+∞,y→0) (1+1/x)^(x^2/(x+y))
1.lim(2x-sinx)/(2x+sinx) (x→0)2.lim(sinsinx)/x (x→0)3.lim 4/y (y→∞)
求极限lim(x,y)→(+∞,+∞) (xy/(x^2+y^2))^x^2
求极限lim(x,y)→(+∞,+∞) [(xy)/(x^2+y^2)]^xy.求极限lim(x,y)→(+∞,+∞) [(xy)/(x^2+y^2)]^xy,
(x→∞,y→∞)lim(x^2+y^2)÷(arctanx+(x-y)^2)求极限
求极限 lim(x→ +∞,y→ +∞) (x^2+y^2)/(x^4+y^4)?
多元函数极限求解lim(x→∞,y→∞)((x+y)/(x^2+xy+y^2))=?
(lim) x/(x-y)
Lim(x+y)/(x2-xy+y2) (x,y)→(∞,∞)这个怎么算Lim(x,y)→(∞,∞) (x+y)/(x2-xy+y2)
lim(x→0y→1)(1+xe^y)^(2y+x/x)求极限
lim(x,y)->(∞,a)(1-1/x)^（x^2/x+y）
证明下列极限不存在(1) Lim x+y/x-y (2)lim x²y²/ x²y²+(x-y)²(x,y)→(0,0) (x,y)→(0,0)
⒈lim(x→a):(sinx-sina)/(x-a) a为常数⒉lim(x→∞):(1+k/x)^(-x) k为常数⒊lim(y→0):(1-5y)^(1/y)
f(x,y)=3xy/x^2+y^2 lim(x→0)(lim(y→0)f(x,y))
求极限：lim (x^2+y^2)^xy（x,y）lim (x^2+y^2)^xy x,y→0 这个极限是多少啊!怎么算?