因式分解 2x^2+5x+32m^2-m-310y^2-y-37-19x-6x^224m^2+m-8-3x^2+5x+21-2x-48x^2-9s^2+30s-25

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因式分解2x^2+5x+32m^2-m-310y^2-y-37-19x-6x^224m^2+m-8-3x^2+5x+21-2x-48x^2-9s^2+30s-25因式分解2x^2+5x+32m^2-m

因式分解 2x^2+5x+32m^2-m-310y^2-y-37-19x-6x^224m^2+m-8-3x^2+5x+21-2x-48x^2-9s^2+30s-25
因式分解
2x^2+5x+3
2m^2-m-3
10y^2-y-3
7-19x-6x^2
24m^2+m-8
-3x^2+5x+2
1-2x-48x^2
-9s^2+30s-25

因式分解 2x^2+5x+32m^2-m-310y^2-y-37-19x-6x^224m^2+m-8-3x^2+5x+21-2x-48x^2-9s^2+30s-25
都是十字相乘
2x^2+5x+3
=(2x+3)(x+1)
2m^2-m-3
=(2m-3)(m+1)
10y^2-y-3
=(5y-3)(2y+1)
7-19x-6x^2
=-(6x^2+19x-7)
=-(3x-1)(2x+7)
24m^2+m-8
这个不能分解
-3x^2+5x+2
=-(3x^2-5x-2)
=-(3x+1)(x-2)
1-2x-48x^2
=-(48x^2+2x-1)
=-(8x-1)(6x+1)
-9s^2+30s-25
=-(9s^2-30s+25)
=-(3s-5)^2

2x^2+5x+3=(2x+3)(x+1)
2m^2-m-3=(2m-3)(m+1)
10y^2-y-3=(2y+1)(5y-3)
7-19x-6x^2=(7+2x)(1-3x)
-3x^2+5x+2=-(3x+1)(x-2)
1-2x-48x^2=(1-8x)(1+6x)
-9s^2+30s-25 =-(3s-5)^2

十字相乘的问题
1.2x^2+5x+3
=(x+1)(2x+3)
2.2m^2-m-3
=(m+1)(m-3)
3.10y^2-y-3
=(2y+1)(5y-3)
4.7-19x-6x^2
=(1-3x)(7+2x)
5.24m^2+m-8
=题目是否有问题
6.-3x^2+5x+2
=-(3x^2-5...

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十字相乘的问题
1.2x^2+5x+3
=(x+1)(2x+3)
2.2m^2-m-3
=(m+1)(m-3)
3.10y^2-y-3
=(2y+1)(5y-3)
4.7-19x-6x^2
=(1-3x)(7+2x)
5.24m^2+m-8
=题目是否有问题
6.-3x^2+5x+2
=-(3x^2-5x-2)
=-(x-2)(3x+1)
7.1-2x-48x^2
=(1+6x)(1-8x)
8.-9s^2+30s-25
=-(9s^2-30s+25 )
=-(3s-5)^2

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都是用十字相乘法啦!就是把平方项的系数和常数项拆分成俩个数相乘。比如说第一道可以这样拆:平方项系数 1 常数项 1
2 3
即1*2=2为平方项系数,1*3=3为常数项,然后交叉相乘:(1*3)+(1*2)=5即为一次项的系数,就可以得到结果,其他题一样 ,我就统一用X来表示未知数吧...

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都是用十字相乘法啦!就是把平方项的系数和常数项拆分成俩个数相乘。比如说第一道可以这样拆:平方项系数 1 常数项 1
2 3
即1*2=2为平方项系数,1*3=3为常数项,然后交叉相乘:(1*3)+(1*2)=5即为一次项的系数,就可以得到结果,其他题一样 ,我就统一用X来表示未知数吧
(X+1)(2X+3)
(X+1)(2X-3)
(2x+1)(5X-3)
(7+2X)(1-3X)
这一道可能你写错了吧!我没办法十字相乘。
(3X+1)(-X+2)
(1+6X)(1-8X)
(-3X+5)(3X-5)

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