实数a,b满足0

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实数a,b满足0实数a,b满足0实数a,b满足0对a^b,b^a取常用对数并做商得blga/(algb)=b/a*logb(a)>1因此lg(a^b)>lg(b^a)a^b>b^a

实数a,b满足0
实数a,b满足0

实数a,b满足0
对a^b,b^a取常用对数并做商得
blga/(algb)=b/a*logb(a)>1
因此lg(a^b)>lg(b^a)
a^b>b^a

实数a,b满足0 实数a,b满足0 1.若实数a,b满足0 若实数a,b满足0 若实数a,b满足0 已知实数a.b满足0 已知实数a,b满足a+b>0,b 实数a.b满足-1 若实数a,b满足a+b 设f(x)=|lgx|,实数a,b满足0 实数A,B,C满足A 已知实数a,b,c,满足a 实数a,b,c满足a 实数a,b,c,d满足a 实数a,b,m,n满足a 若实数a,b,c,d满足c>0,d若实数a,b,c,d满足c>0,d 已知实数a、b满足实数(a+b)^2+a+b-2=0,求a+b的值已知实数a满足0