y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
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y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
因为：y=3sin(π/6-3x)
所以：y'=3cos(π/6-3x)(-3)=-9cos(π/6-3x)
令：y'≥0,有：
-9cos(π/6-3x)≥0
cos(π/6-3x)≤0
所以：3π/2≥π/6-3x≥π/2
解得：-4π/9≤x≤π/9
即：单调增区间是：x∈(-4π/9,π/9)
-π/2<=x<=π/2
-3π/2<=3x<=3π/2
-3π/2<=-3x<=3π/2
π/6-3π/2<=π/6-3x<=3π/2+π/6
-4π/3<=π/6-3x<=5π/3
单调增区间：-π/2<=π/6-3x<=π/2
-π/2<=3x-π/6<=π/2
-π/3<=3x<=2π/3
-π/9<=x<=2π/9
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