y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/18 17:25:05
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
y=3sin(π/6-3x),x∈[-π/2,π.2]的单调增区间是
因为：y=3sin(π/6-3x)
所以：y'=3cos(π/6-3x)(-3)=-9cos(π/6-3x)
令：y'≥0,有：
-9cos(π/6-3x)≥0
cos(π/6-3x)≤0
所以：3π/2≥π/6-3x≥π/2
解得：-4π/9≤x≤π/9
即：单调增区间是：x∈(-4π/9,π/9)
-π/2<=x<=π/2
-3π/2<=3x<=3π/2
-3π/2<=-3x<=3π/2
π/6-3π/2<=π/6-3x<=3π/2+π/6
-4π/3<=π/6-3x<=5π/3
单调增区间：-π/2<=π/6-3x<=π/2
-π/2<=3x-π/6<=π/2
-π/3<=3x<=2π/3
-π/9<=x<=2π/9
判断单调性 y=sin(x-π/6) y=sin(-2x+π/3)
已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值
y=sin(x+π/3)周期
函数y=4sin(x+π/6)+3sin(π/3-x)的最大值是多少
函数y=2sin(π/3-X)+sin(π/6+X)的最大值
y=12sin(2x+π/6)+5sin(π/3-2x)最大值
y=12sin(2x+π/6)+5sin(π/3-2x)的最大值
y=sin(x-π/6)sin(x+π/3)最小正周期
y=sin(2x+π/6),x∈[π/4,3π/4]求值域
求函数的值域y=sin(2x+π/3),x∈(-π/6,π)
求y=sin(2x+π/6)x∈(0,π/3)的值域
y=sin(π/6-3x),x∈[0,π/4]的单调区间.
y=3sin(π/6-3x)的周期
y=3sin(4/3x+π/6)周期
y=sin(3x-π/6)的导数
y=2sin三分之一x y=4sin(x-π/3) y=sin(2x+π/6) y=3sin(1/2x-π/4) 的周期各是多少,
求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6)
y=sin(x-π/6) 和 y=1/2sin(π/3-2x) 的单增区间,