设f(x)=sin(2x+a)(-π
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设f(x)=sin(2x+a)(-π设f(x)=sin(2x+a)(-π设f(x)=sin(2x+a)(-π(3)设函数f(x)=sin[2x-(3π/4)],证明:直线5x-2y+c=0与函数y=f
设f(x)=sin(2x+a)(-π
设f(x)=sin(2x+a)(-π
设f(x)=sin(2x+a)(-π
(3)设函数f(x)=sin[2x-(3π/4)],证明:直线5x-2y+c=0与函数y=f(x)的图象不相切.
f(x)=sin(2x-3π/4)
--->f'(x)=2cos(2x-3π/4)≤2,即f(x)的切线斜率不大于2
又直线5x-2y+c=0斜率=5/2>2
∴直线5x-2y+c=0与函数y=f(x)的图象不可能相切
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