设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 18:52:36
设f(0)=0,f''(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?设f(0)=0,f''(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?设f(0)=0,f''
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
lim(x趋近于0)=(f(x-sinx))/x^3 (分子趋于f(0)=0分母趋于0,罗比达法则)
=lim(x->0) f'(x-sinx)*(1-cosx)/3x^2
=lim(x->0) f'(x-sinx)*lim(x->0) (1-cosx)/3x^2
=f'(0)*lim(x->0) {1-[1-2(sinx/2)^2}/3x^2
=6*lim (x->0) 2(sinx/2)^2/(3x^2)
=6*2*lim (x->0) (x/2)^2/(3x^2)
=6*2*1/12=1
设lim(x→0)[f(x)-3]/x^2=100,求lim(x→0)f(x)
设f(x)=1/(1+e^(1/x)) 求 lim f(x) x->0
设f(0)=0,f'(0)存在,求lim(x→o)f(x)/x.
关于微分设f(a)=4,求lim[f(a+k)-f(a)]/3k k→0
设f'(x)=2,求极限lim(x~0)[f(1-x)-f(1+x)]/x
设f(x)=当x0时为arccot-2/(x^2),求lim f(x) x->0-,lim f(x)x->0+,limf(x) x->0
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?详细点
设f(0)=0,f'(0)=6,求lim(x趋近于0)=(f(x-sinx))/x^3=?
设f(x)具有一阶连续导数,f(0)=0,f'(0)=2,求了lim(x→0)f(1-cosx)/tan(x^2)
设f(x0)存在,试用导数定义求下列极限 lim(x→0)f(x)/x,其中f(0)=0,且f'(0)存在
设函数f(x)有连续的导数,并且f(0)=f'(0)=1,求lim(x-->0){[f(sinx)-1]/Inf(x)}?需过程
设F(x)=∫(0趋向x) [(x-t)f(t)dt]/(sinx)^2 求lim(x趋向0)F(x),f(0)存在,
设f(x)在x=a处可导,f'(x)=b 求极限lim(h-0) f(a-h)-f(a+2h)/ hRT
设函数f(x)可导,且f′(3)=2,求lim(x→0)[f(3-x)-f(3)]/2x
设函数 f(x)可导,且f'(3)=2,求 x->0 lim [f(3-3)-f(3)]/2x
设f(x)在x=a处可导,f(a)>0,求N趋近于正无穷时lim{f(a+1/n)/f(a)}的N次方.
设y=f(x)在点x0处可导,且f(x0)为最大值,求lim△x→0 f(xo+△x)-f(x0)/△x