5ax+5bx+3ay+3by
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5ax+5bx+3ay+3by5ax+5bx+3ay+3by5ax+5bx+3ay+3by原式=(5ax+5bx)+(3ay+3by)=5x(a+b)+3y(a+b)=(a+b)(5x+3y)原式=a
5ax+5bx+3ay+3by
5ax+5bx+3ay+3by
5ax+5bx+3ay+3by
原式= (5ax+5bx)+(3ay+3by)
=5x(a+b)+3y(a+b)
=(a+b)(5x+3y)
原式=a(5x+3y)+b(5x+3y)
=(a+b)(5x+3y)
5ax+5bx+3ay+3by
因式分解(1)2ax-10ay+5by-bx(2)x²+xy+bx+ax+by+ay(1)x²+3x-4
ax+by-ay-bx
ax-bx-ay+by
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已知实数abxy满足ax+by=3,ay-bx=5已知实数a,b,x,y满足ax+by=3,ay-bx=5,则(a^2+b^2)(x^2+y^2)的值是多少
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证明|by+az bz+ax bx+ay| |x y z||bx+ay by+az bz+ax| =( a^3+b^3 ) |z x y||bz+ax bx+ay by+az| |y z x|
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