若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=

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若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=(x-2)^2+(y

若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=
若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=

若(x-2)^2+(y-1)^2=0,则-x^2y+2xy=
(x-2)^2+(y-1)^2=0
因为平方不可能是负数,所以x=2, y=1.
-x^2y+2xy=-2^2+2*2*1=-4+4=0