若|x-2y+1|+|x+y-5|=0,则2^2+y^2
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若|x-2y+1|+|x+y-5|=0,则2^2+y^2若|x-2y+1|+|x+y-5|=0,则2^2+y^2若|x-2y+1|+|x+y-5|=0,则2^2+y^2因为|x-2y+1|≥0,|x+
若|x-2y+1|+|x+y-5|=0,则2^2+y^2
若|x-2y+1|+|x+y-5|=0,则2^2+y^2
若|x-2y+1|+|x+y-5|=0,则2^2+y^2
因为|x-2y+1|≥0,|x+y-5|≥0,且|x-2y+1|+|x+y-5|=0
所以 x-2y+1=0
x+y-5=0
解方程组得x=3,y=2
所以x^2+y^2=13
题目不对,解不出来
由题意可知
x-2y+1=0
x+y-5=0
解之得 x=3, y=2
所以2^2+y^2=4+4=8
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