如何化简下列算式1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005) 如何求解下面的分式方程1/x(x+2)+1/(

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 12:33:19
如何化简下列算式1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005)如何求解下面的分式方程1/x(x+2)+1/(如何化简下列算式1/x+1/x(x+1)+

如何化简下列算式1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005) 如何求解下面的分式方程1/x(x+2)+1/(
如何化简下列算式1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005) 如何求解下面的分式方程1/x(x+2)+1/(

如何化简下列算式1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005) 如何求解下面的分式方程1/x(x+2)+1/(
1/x+1/x(x+1)+1/(x+1)(x+2)+...+1/(x+2004)(x+2005)
=1/x + 1/x -1/(x+1)+1/(x+1)-1/(x+2)+...+1/(x+2004)-1/(x+2005)
=1/x+1/x-1/(x+2005)
= [2(x+2005)-x]/[ x(x+2005)]
=(x+4010)/[ x(x+2005)]
同理
1/x(x+2) =1/2 [1/X-1/(X+2)]