(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简
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(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^
(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简
(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简
(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简
把题目写清楚先
我没猜错的话应该是这个
[1/(a-b)-1/(a+b)]÷[b/(a^2-2ab+b^2)]
=[2b/(a-b)(a+b)]÷[b/(a-b)^2]
=2(a-b)/(a+b)
纯粹拜访高人
(a/a-b - b/a+b)÷2b/a²-b² 其中a=-2,b=1
-a+b÷a+b=a+b÷-(a+b)=1对吗
计算(a-b分之1-a²-b²分之b)÷a+b分之a
化简(1/a-b - b/a²-b²)÷a/a+b
a/a²-b-1/a+b
计算:a/b(a-b)-b/a(a-b);(1/a+1/b)÷a²+2ab+b²/a+b.
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
b/a(b+1) a/b(b+1)
(a+b)(a²-ab+b²)-b(b-1)
计算:(b/a)^2÷(a/b)-b^3/a^3(a-b) ÷ 1/a-b
a+b a-b----- -- ------a-b a+b -------------------------1------a^2 -b^2
b>1,a÷b>1对吗?
(1/(a-b)-1/(a+b)÷b/(a^2-2ab+b^2),化简
化简:[(2a-b)²-4b(a+1/4b)] ÷(2a-4b)
比大小:a÷b()a(a>0,b>1)
比大小:a÷b()a(a>0,b>1)
b/a,a/b,1/(a-b)通分
a-b分之a+b-a分之b+1